class Solution(object):
def minimumTotal(self, triangle):
"""
:type triangle: List[List[int]]
:rtype: int
"""
#work from bottom up
if not triangle:
return 0
n=len(triangle)
dp=triangle[n-1]
for i in reversed(xrange(n-1)):
for j in xrange(i+1):
dp[j]=min(dp[j],dp[j+1])+triangle[i][j]
return dp[0]
120. Triangle Given a triangle, find the minimum path sum...
10-16 LeetCode 120. Triangle Triangle Description Given a...
//120. TriangleGiven a triangle, find the minimum path su...
top to down的方案状态转移： f(x,y) = min(f(x-1, y-1), f(x-1, y)) ...
Given a triangle, find the minimum path sum from top to b...
https://leetcode.com/problems/triangle/description/解题思路：d...
题目 思路 动态规划的题目。 递归 二维数组保存dp[i][j]：到(i,j)位置时的最小值 自底向上一维数组 ...
题目 Given a triangle, find the minimum path sum from top t...
从底部往上算，递归公式: dp(i,j) 表示从tri[i][j]到底部位置的最小的sum。 dp(i,j) = ...
Given a triangle, find the minimum path sum from top to b...
本文标题：120. Triangle
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