1065 A+B and C (64bit)
作者:
梅友泥撑 | 来源:发表于
2025-04-20 12:40 被阅读0次#include<iostream>
typedef long long LL;
using namespace std;
int main() {
int t;
LL a, b, c;
bool flag;
scanf("%d", &t);
for (int i = 1; i <= t; i++) {
scanf("%lld%lld%lld", &a, &b, &c);
LL sum = a + b;//要判断溢出
if (a > 0 && b > 0 && sum < 0) {
flag = true;
}
else if (a < 0 && b < 0 && sum>0) {
flag = false;
}
else if (sum > c) {
flag = true;
}
else {
flag = false;
}
if (flag) {
printf("Case #%d: true\n", i);
}
else {
printf("Case #%d: false\n", i);
}
}
return 0;
}
本文标题:1065 A+B and C (64bit)
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