My code:
public class Solution {
// you need treat n as an unsigned value
public int reverseBits(int n) {
int result = 0;
for (int i = 0; i < 32; i++) {
result |= ((n >> i) & 1) << (31 - i);
}
return result;
}
}
reference:
https://discuss.leetcode.com/topic/53210/easy-understand-java-solution-with-comments
Anyway, Good luck, Richardo! -- 09/28/2016
LeetCode 190 Reverse Bits ======================= Reverse...
LeetCode 190. Reverse Bits Description Example 1: Input: ...
Leetcode: 190. Reverse BitsReverse bits of a given 32 bit...
题目描述： https://leetcode.com/problems/reverse-bits/Code:
题目地址 https://leetcode.com/problems/reverse-bits/[https://...
My code: reference:https://discuss.leetcode.com/topic/532...
Reverse Bits Reverse bits of a given 32 bits unsigned int...
190. 颠倒二进制位[https://leetcode-cn.com/problems/reverse-bits...
190. 颠倒二进制位 https://leetcode-cn.com/problems/reverse-bits...
题目： Reverse bits of a given 32 bits unsigned integer.Exam...
本文标题：Leetcode - Reverse Bits
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