class Solution:
def search(self, nums: List[int], target: int) -> int:
left = 0
right = len(nums) -1
while left <= right:
mid = left + ((right-left)>>2)
if nums[mid] == target:
return mid
elif nums[mid] > target:
right = mid - 1
else:
left = mid + 1
return -1
704. 二分查找[https://leetcode-cn.com/problems/binary-search/...
704. 二分查找[https://leetcode-cn.com/problems/binary-search/...
704. 二分查找[https://leetcode-cn.com/problems/binary-search/...
二分查找法 (Binary Search) 二分查找也称折半查找（Binary Search），它是一种效率较高的...
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704.二分查找 题目链接704. 二分查找 - 力扣（LeetCode）[https://leetcode.cn...
本文标题：704. Binary Search二分查找
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