链表的反转
作者:
Peter杰 | 来源:发表于
2019-08-26 19:12 被阅读0次//递归
public ListNode reverseList(ListNode head) {
if (head == null) {
return null;
}
if (head.next==null) {
return head;
}
ListNode newHead = reverseList(head.next);
head.next.next = head;
head.next = null;
return newHead;
}
//非递归
public ListNode reverseList2(ListNode head) {
if (head == null) {
return null;
}
if (head.next==null) {
return head;
}
ListNode newHead = null;
while (head != null) {
ListNode tmp = head.next;
head.next = newHead;
newHead = head;
head = tmp;
}
return newHead;
}
本文标题:链表的反转
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