iOS 对某页面禁用 左侧滑pop返回的手势

通过询问ChatG-PT，稍作修改，终于找到两种方式，代码如下：

import React, { Component, useEffect, useContext } from 'react';
import { View } from 'react-native';
import { Actions, Scene, Router } from 'react-native-router-flux';

const MyScene = () => {

  useEffect(() => {
    setTimeout(() => {
      Actions.scene2()
    }, 1000);
  }, [])

  return (
    <View style={{ flex: 1 }}>
      {/* 页面内容 */}
    </View>
  );
};

const MyScene2 = () => {
  useEffect(() => {
    setTimeout(() => {
      Actions.scene3()
    }, 1000);
  }, [])

  return (
    <View style={{ flex: 1 }}>
      {/* 页面内容 */}
    </View>
  );
};


class MyScene3 extends Component {
  // 方式一
  // static navigationOptions = {
  //   gesturesEnabled: false, // 禁用左滑返回手势
  // };

  render() {
    return (
      <View>
        {/* 页面内容 */}
      </View>
    );
  }
};


const App = () => {
  return (
    <Router>
      <Scene key="root" modal={true}>
        <Scene key="scene1" component={MyScene} title="Scene 1" />
        <Scene
          key="scene2"
          component={MyScene2}
          title="Scene 2"
        // gesturesEnabled={false}
        />
        <Scene key="scene3" component={MyScene3} title="Scene 3"
          // 方式二
          gesturesEnabled={false}
        />
      </Scene>
    </Router>
  );
};

export default App;