HDU 2055 An easy problem

Problem Description

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

Input
On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.

Output
for each case, you should the result of y+f(x) on a line.

Sample Input

6 R 1 P 2 G 3 r 1 p 2 g 3

Sample Output

19 18 10 -17 -14 -4

JAVA CODE

import java.util.Scanner;
public class Main {
    public static void main(String[] args) {
        Scanner cin = new Scanner(System.in);
        int n = cin.nextInt();
        for (int i = 0; i < n; i++) {
            String string = cin.next();
            int number = cin.nextInt();
            int sum = 0;
            if (Character.isUpperCase(string.charAt(0))) {
                sum = string.charAt(0) - 'A' + number + 1;
            } else if (Character.isLowerCase(string.charAt(0))) {
                sum = 'a' - string.charAt(0) + number - 1;
            }
            System.out.println(sum);
        }
        cin.close();
    }

}```