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[LeetCode]462. Minimum Moves to

[LeetCode]462. Minimum Moves to

作者: Eazow | 来源:发表于2017-05-26 20:57 被阅读122次

Given a non-empty integer array, find the minimum number of moves required to make all array elements equal, where a move is incrementing a selected element by 1 or decrementing a selected element by 1.

You may assume the array's length is at most 10,000.

Example:

Input:
[1,2,3]
Output:
2
Explanation:
Only two moves are needed (remember each move increments or decrements one element):
[1,2,3]  =>  [2,2,3]  =>  [2,2,2]
难度

Medium

方法

对数组排序,取中间的元素,然后求出每个元素和该元素的差值,将差值累加即为最终结果

python代码
class Solution(object):
    def minMoves2(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        nums.sort()
        moves = 0
        medium = len(nums)/2
        for i in xrange(len(nums)):
            moves += abs(nums[i]-nums[medium])

        return moves

assert Solution().minMoves2([1,2,3]) == 2

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