1.最长回文 2.词句模式 3.字句分组 4.最长不重复序列 5

    int longestPalindrome(string s) {
        int odds = 0;
        for (char c = 'A'; c <= 'z'; ++c) {
            odds += count(s.begin(), s.end(), c) & 1;
        }
        return s.size() - max(0, odds - 1);
    }

bool wordPattern(string pattern, string str) {
        unordered_map<char, int> m1;
        unordered_map<string, int> m2;
        istringstream in(str);
        int i = 0;
        for (string word; in >> word; ++i) {
            if (m1.find(pattern[i]) != m1.end() || m2.find(word) != m2.end()) {
                if (m1[pattern[i]] != m2[word]) return false;
            } else {
                m1[pattern[i]] = m2[word] = i + 1;
            }
        }
        return i == pattern.size();
    }

    vector<vector<string>> groupAnagrams(vector<string>& strs) {
        vector<vector<string>> res;
        unordered_map<string, vector<string>> m;
        for (string str : strs) {
            string t = str;
            sort(t.begin(), t.end());
            m[t].push_back(str);
        }
        for (auto a : m) {
            res.push_back(a.second);
        }
        return res;
    }

    int lengthOfLongestSubstring(string s) {
        int m[256] = {0}, res = 0, left = 0;
        for (int i = 0; i < s.size(); ++i) {
            if (m[s[i]] == 0 || m[s[i]] < left) {
                res = max(res, i - left + 1);
            } else {
                left = m[s[i]];
            }
            m[s[i]] = i + 1;
        }
        return res;
    }

void reversedword(char *front,char *end){
    while (front<end)
    {
        char tmp=*front;
        *front++=*end;
        *end--=tmp;
    }
}

char *reverse(char *s)
{
    char *pre=s;
    char *cur=s;
    while(*cur!='\0')
        if (*cur==' ')
        {
            reversedword(pre,cur-1);
            cur++;
            pre=cur;
        }
        else
        {
            cur++;
        }
    reversedword(pre,cur-1);
    reversedword(s,cur-1);
    return s;
}