问题
X 市建了一个新的体育馆,每日人流量信息被记录在这三列信息中:序号 (id)、日期 (visit_date)、 人流量 (people)。
请编写一个查询语句,找出人流量的高峰期。高峰期时,至少连续三行记录中的人流量不少于100。
例如,表 stadium:
| id | visit_date | people |
|---|---|---|
| 1 | 2017-01-01 | 10 |
| 2 | 2017-01-02 | 109 |
| 3 | 2017-01-03 | 150 |
| 4 | 2017-01-04 | 99 |
| 5 | 2017-01-05 | 145 |
| 6 | 2017-01-06 | 1455 |
| 7 | 2017-01-07 | 199 |
| 8 | 2017-01-08 | 188 |
对于上面的示例数据,输出为:
| id | visit_date | people |
|---|---|---|
| 5 | 2017-01-05 | 145 |
| 6 | 2017-01-06 | 1455 |
| 7 | 2017-01-07 | 199 |
| 8 | 2017-01-08 | 188 |
提示:
每天只有一行记录,日期随着 id 的增加而增加。
准备
create database leecote601;
use leecote601;
create table stadium (
id int(20),
visit_date date,
people int(20));
insert into stadium values
(1,'2017-01-01',10),
(2,'2017-01-02',109),
(3,'2017-01-03',150),
(4,'2017-01-04',99),
(5,'2017-01-05',145),
(6,'2017-01-06',1455),
(7,'2017-01-07',199),
(8,'2017-01-08',188);
解答
select distinct t1.*
from stadium t1, stadium t2, stadium t3
where t1.people >= 100 and t2.people >= 100 and t3.people >= 100
and
(
(t1.id - t2.id = 1 and t1.id - t3.id = 2 and t2.id - t3.id =1) -- t1, t2, t3
or
(t2.id - t1.id = 1 and t2.id - t3.id = 2 and t1.id - t3.id =1) -- t2, t1, t3
or
(t3.id - t2.id = 1 and t2.id - t1.id =1 and t3.id - t1.id = 2) -- t3, t2, t1
)
;











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