| * | * |
|---|---|
| 链接 | Complementary DNA |
| 难度 | 8kyu |
| 状态 | √ |
| 日期 | 2018-12-05 |
def DNA_strand(dna):
# code here
dnaList = list(dna)
for i in range(len(dnaList)):
if dnaList[i] == 'A':
dnaList[i] = 'T'
elif dnaList[i] == 'T':
dnaList[i] = 'A'
elif dnaList[i] == 'C':
dnaList[i] = 'G'
elif dnaList[i] == 'G':
dnaList[i] = 'C'
return "".join(dnaList)
题意 题解1
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本文标题：Complementary DNA
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