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20. Valid Parentheses

20. Valid Parentheses

作者: Nancyberry | 来源:发表于2018-06-20 11:50 被阅读0次

Description

Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid.

An input string is valid if:

  1. Open brackets must be closed by the same type of brackets.
  2. Open brackets must be closed in the correct order.

Note that an empty string is also considered valid.

Example 1:

Input: "()"
Output: true

Example 2:

Input: "()[]{}"
Output: true

Example 3:

Input: "(]"
Output: false

Example 4:

Input: "([)]"
Output: false

Example 5:

Input: "{[]}"
Output: true

Solution

Stack, O(n), S(n)

很聪明的写法:

class Solution {
    public boolean isValid(String s) {
        if (s == null) {
            return false;
        }
        
        Stack<Character> stack = new Stack<>();
        for (char c : s.toCharArray()) {
            if (c == '(') {
                stack.push(')');
            } else if (c == '[') {
                stack.push(']');
            } else if (c == '{') {
                stack.push('}');
            } else if (stack.isEmpty() || c != stack.pop()) {
                return false;
            }
        }
        
        return stack.isEmpty();
    }
}

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