awk 统计某一列1，2，3......20 >20 的数

awk '{if($2=="1") ++sum1;if($2=="2") ++sum2;if($2=="3") ++sum3;if($2=="4") ++sum4;if($2=="5") ++sum5;if($2=="6") ++sum6;if($2=="7") ++sum7;if($2=="8") ++sum8;if($2=="9") ++sum9;if($2=="10") ++sum10;if($2=="11") ++sum11;if($2=="12") ++sum12;if($2=="13") ++sum13;if($2=="14") ++sum14;if($2=="15") ++sum15;if($2=="16") ++sum16;if($2=="17") ++sum17;if($2=="18") ++sum18;if($2=="19") ++sum19;if($2=="20") ++sum20;if($2>"20") ++sum21;}END{print "1""\t"sum1"\n""2""\t"sum2"\n""3""\t"sum3"\n""4""\t"sum4"\n""5""\t"sum5"\n""6""\t"sum6"\n""7""\t"sum7"\n""8""\t"sum8"\n""9""\t"sum9"\n""10""\t"sum10"\n""11""\t"sum11"\n""12""\t"sum12"\n""13""\t"sum13"\n""14""\t"sum14"\n""15""\t"sum15"\n""16""\t"sum16"\n""17""\t"sum17"\n""18""\t"sum18"\n""19""\t"sum19"\n""20""\t"sum20"\n"">20""\t"sum21"\n"}' 1.txt