给定一个整数 n,求以 1 ... n 为节点组成的二叉搜索树有多少种?
示例:
输入: 3
输出: 5
解释:
给定 n = 3, 一共有 5 种不同结构的二叉搜索树:
1 3 3 2 1
\ / / / \ \
3 2 1 1 3 2
/ / \ \
2 1 2 3
package main
import "fmt"
func main(){
fmt.Println(numTrees(3))
}
func numTrees(n int) int {
//每棵树的组合都是要依赖子树的变化
numTreeCount := make([]int, n+1)
numTreeCount[0], numTreeCount[1] = 1, 1
for i := 2; i <= n; i++ {
for j := 1; j <= i; j++ {
numTreeCount[i] += numTreeCount[j-1] * numTreeCount[i-j]
}
}
return numTreeCount[n]
}












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