链表
动态数据结构,可以更加深入的理解引用(指针)。数据存储在节点中,每个链表中的节点都包含一个值,和指向下一个节点的指针。(缺点:无法随机访问一个节点)
相应操作
创建一个链表示例(Java)
public class LinkedList <E>{
private class Node{
public E e;
public Node next;
public Node(E e, Node next) {
this.e = e;
this.next = next;
}
public Node(E e){
this(e, null);
}
public Node() {
this(null, null);
}
@Override
public String toString() {
return e.toString();
}
}
private Node dummyHead;
int size;
public LinkedList(){
dummyHead = new Node(null, null);
size = 0;
}
//获取链表中元素的个数
public int getSize(){
return size;
}
//返回链表是否为空
public boolean isEmpty() {
return size == 0;
}
}
添加一个元素示例(Java)
//在链表的index(0-based)位置添加新的元素e
public void add(int index, E e){
if (index < 0 || index > size)
throw new IllegalArgumentException("Add failed, Illegal index");
Node prev = dummyHead;
for (int i = 0; i < index; i ++)
prev = prev.next;
// Node node = new Node(e);
// node.next = prev.next;
// prev.next = node;
prev.next = new Node(e, prev.next);
size ++;
}
//在链表头添加元素e
public void addFirst(E e) {
add(0, e);
}
//在链表末尾添加新的元素e
public void addLast(E e){
add(size, e);
}
//获取链表的index(0-based)个位置的元素;
public E get(int index){
if (index < 0 || index > size)
throw new IllegalArgumentException("Get failed, Illegal index");
Node cur = dummyHead.next;
for (int i = 0; i < index; i++)
cur = cur.next;
return cur.e;
}
//获得链表的第一个元素
public E getFirst() {
return get(0);
}
//获得链表的最后一个元素
public E getLast() {
return get(size - 1);
}
修改一个元素示例(Java)
//修改链表的第index(0 - based)个位置的元素
public void set(int index, E e){
if (index < 0 || index > size)
throw new IllegalArgumentException("Set failed, Illegal index");
Node cur = dummyHead.next;
for (int i = 0; i < index; I++)
cur = cur.next;
cur.e = e;
}
查找一个元素示例(Java)
//查找链表中是否有元素e
public boolean contains(E e){
Node cur = dummyHead.next;
while (cur != null) {
if (cur.e.equals(e))
return true;
cur = cur.next;
}
return false;
}
删除一个元素示例(Java)

//删除链表中index(0 - based)位置的元素, 返回删除的元素
public E remove(int index){
if (index < 0 || index > size)
throw new IllegalArgumentException("Remove failed, Illegal index");
Node prev = dummyHead;
for (int i = 0; i < index; I++)
prev = prev.next;
Node retNode = prev.next;
prev.next = retNode.next;
retNode.next = null;
size --;
return retNode.e;
}
//删除链表中第一个元素并返回
public E removeFirst(){
return remove(0);
}
//删除链表中最后一个元素并返回
public E removeLast() {
return remove(size - 1);
}
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