列出目录占用磁盘空间大于100M的目录
du -k | awk '$1>102400{print $1/1024"M "$2}'
列出文件大小大于100M的文件
#!/bin/bash
# find file depth
dep=1
# exclude files, use '|' segmentation. (cause: sbin link /usr/sbin , bin link /usr/bin ...)
excludeFiles='proc|dev|boot|bin|sbin|lib|lib64'
# file or dir max size(M), 100 => 100M
dirMaxSize=300
fileMaxSize=100
# find under / mindepth 1 maxdepth $dep directory
find `ls / | grep -Ev $excludeFiles | sed -rn 's#(.*)#/\1#p'` -mindepth 1 -maxdepth $dep -type d | while read d;
do
dirSizeResult=`du -sm $d`
size=`echo $dirSizeResult|awk '{print $1}'`
if [ $size -ge $dirMaxSize ];then
echo $dirSizeResult
find $d -type f -size +${fileMaxSize}M -exec ls -lh {} \;
fi
done
网友评论