| * | * |
|---|---|
| 链接 | SQL Basics: Simple JOIN with COUNT |
| 难度 | 7kyu |
| 状态 | √ |
| 日期 | 2019-5-13 |
题意
题解1
select people.id , people.name , count(toys.id) as toy_count
from people
left join toys
on people.id = toys.people_id
group by people.id
| * | * |
|---|---|
| 链接 | SQL Basics: Simple JOIN with COUNT |
| 难度 | 7kyu |
| 状态 | √ |
| 日期 | 2019-5-13 |
select people.id , people.name , count(toys.id) as toy_count
from people
left join toys
on people.id = toys.people_id
group by people.id题意 题解1
题意 题解1
题意 题解1
题意 题解1
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题意 题解1
题意 题解1 题解2-wrong 题解-LZY
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本文标题：SQL Basics: Simple JOIN with COU
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