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[刷题防痴呆] 0355 - 设计推特 (Design Twit

[刷题防痴呆] 0355 - 设计推特 (Design Twit

作者: 西出玉门东望长安 | 来源:发表于2022-03-24 00:01 被阅读0次

题目地址

https://leetcode.com/problems/design-twitter/

题目描述

355. Design Twitter

Design a simplified version of Twitter where users can post tweets, follow/unfollow another user, and is able to see the 10 most recent tweets in the user's news feed.

Implement the Twitter class:

Twitter() Initializes your twitter object.
void postTweet(int userId, int tweetId) Composes a new tweet with ID tweetId by the user userId. Each call to this function will be made with a unique tweetId.
List<Integer> getNewsFeed(int userId) Retrieves the 10 most recent tweet IDs in the user's news feed. Each item in the news feed must be posted by users who the user followed or by the user themself. Tweets must be ordered from most recent to least recent.
void follow(int followerId, int followeeId) The user with ID followerId started following the user with ID followeeId.
void unfollow(int followerId, int followeeId) The user with ID followerId started unfollowing the user with ID followeeId.
 

Example 1:

Input
["Twitter", "postTweet", "getNewsFeed", "follow", "postTweet", "getNewsFeed", "unfollow", "getNewsFeed"]
[[], [1, 5], [1], [1, 2], [2, 6], [1], [1, 2], [1]]
Output
[null, null, [5], null, null, [6, 5], null, [5]]

Explanation
Twitter twitter = new Twitter();
twitter.postTweet(1, 5); // User 1 posts a new tweet (id = 5).
twitter.getNewsFeed(1);  // User 1's news feed should return a list with 1 tweet id -> [5]. return [5]
twitter.follow(1, 2);    // User 1 follows user 2.
twitter.postTweet(2, 6); // User 2 posts a new tweet (id = 6).
twitter.getNewsFeed(1);  // User 1's news feed should return a list with 2 tweet ids -> [6, 5]. Tweet id 6 should precede tweet id 5 because it is posted after tweet id 5.
twitter.unfollow(1, 2);  // User 1 unfollows user 2.
twitter.getNewsFeed(1);  // User 1's news feed should return a list with 1 tweet id -> [5], since user 1 is no longer following user 2.

思路

  • 数据结构.
  • 开个list存储tweet.
  • 开个map保存follow信息.
  • 倒序遍历list输出前十条tweet.

关键点

代码

  • 语言支持:Java
class Twitter {

    class Tweet {
        int userId;
        int tweetId;
    }
    
    List<Tweet> list;
    Map<Integer, Set<Integer>> map;

    public Twitter() {
        list = new ArrayList<>();
        map = new HashMap<>();
    }
    
    public void postTweet(int userId, int tweetId) {
        Tweet tweet = new Tweet();
        tweet.userId = userId;
        tweet.tweetId = tweetId;
        follow(userId, userId);
        list.add(tweet);
    }
    
    public List<Integer> getNewsFeed(int userId) {
        List<Integer> res = new ArrayList<>();
        Set<Integer> set = map.get(userId);
        int count = 0;
        for (int i = list.size() - 1; i >= 0; i--) {
            Tweet tweet = list.get(i);
            if (count < 10 && set.contains(tweet.userId)) {
                res.add(tweet.tweetId);
                count++;
            }
        }
        return res;
    }
    
    public void follow(int followerId, int followeeId) {
        map.putIfAbsent(followerId, new HashSet<>());
        map.get(followerId).add(followeeId);
    }
    
    public void unfollow(int followerId, int followeeId) {
        map.get(followerId).remove(followeeId);
    }
}

/**
 * Your Twitter object will be instantiated and called as such:
 * Twitter obj = new Twitter();
 * obj.postTweet(userId,tweetId);
 * List<Integer> param_2 = obj.getNewsFeed(userId);
 * obj.follow(followerId,followeeId);
 * obj.unfollow(followerId,followeeId);
 */

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