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springboot中使用@Validate不生效的原因

springboot中使用@Validate不生效的原因

作者: Gason_d796 | 来源:发表于2021-01-07 09:29 被阅读0次

问题:使用validate相关注解却没用生效的问题

public class LoginRequest implements Serializable {

    private static final long serialVersionUID = 1L;

    @ApiModelProperty(value = "手机号", required = true, example = "18888888")
    @Pattern(regexp = RegularConstants.PHONE, message = "手机号码格式错误")
    @JsonProperty(value = "phone")
    private String phone;

    @ApiModelProperty(value = "密码", required = true, example = "1~[6,18]")
    @Pattern(regexp = RegularConstants.PASSWORD, message = "密码格式错误,密码必须以字母开头,长度在6~18之间,只能包含字符、数字和下划线")
    private String password;

}

解决

  • 引入hibernate相关依赖
       <dependency>
            <groupId>org.hibernate.validator</groupId>
            <artifactId>hibernate-validator</artifactId>
            <version>6.0.21.Final</version>
        </dependency>
        <dependency>
            <groupId>javax.el</groupId>
            <artifactId>javax.el-api</artifactId>
            <version>3.0.0</version>
        </dependency>
  • 相关配置
@Configuration
public class ValidatorConfiguration {
    @Bean
    public Validator validator() {
        ValidatorFactory validatorFactory = Validation.byProvider(HibernateValidator.class)
                .configure()
                .addProperty("hibernate.validator.fail_fast", "true")
                .buildValidatorFactory();
        return validatorFactory.getValidator();
    }
}
  • 全局拦截验证错误
@RestControllerAdvice
public class WebGlobalExceptionHandler {
//    private static final Logger logger = LoggerFactory.getLogger(GlobalExceptionHandler.class);
    /**
     * 拦截JSON参数校验
     */
//    @ResponseStatus(HttpStatus.OK)
    @ExceptionHandler(MethodArgumentNotValidException.class)
    public CommonResult bindException(MethodArgumentNotValidException e) {
        BindingResult bindingResult = e.getBindingResult();
        return CommonResult.failed(ExceptionCodeEnum.VALIDATE_FAILED,Objects.requireNonNull(bindingResult.getFieldError()).getDefaultMessage());
    }
}

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