python字典反查

下面这一段代码实现了取一个字典中top10，涉及到字典反查并去重

def rank(top):

    vals = list(top.values())

    print(vals)

    vals.sort(reverse = True)

    print(vals)

    if len(vals) > 10:

        vals = vals[:10]

    print(vals)

    # 去重

    new_vals = []

    for i in vals:

        if i not in new_vals:

            new_vals.append(i)

    print(new_vals)

    top10 = []

    for val in new_vals:

        k = [k for k, v in top.items() if v == val]

        #print(k)

        for s in k:

            top10.append({'name':s,'count':val})

    if len(top10) > 10:

        top10 = top10[:10]

    print(top10)

top1 = {'a':22, 'b':33, 'c':44, 'd':55, 'e':33, 'f':55, 'g':13, 'h':1, 'i':2, 'j':3, 'k':5, 'l':0, 'm':0, 'root_copy':0}

top2 = {'a':1, 'b':2, 'c':8, 'd':5, 'e':5, 'f':4}

rank(top1)

print(top1)