给定一个二叉树,返回它的 后序 遍历。
示例:
输入: [1,null,2,3]
1
2
/
3
输出: [3,2,1]
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
递归
class Solution {
List<Integer> lists = new ArrayList<>();
public List<Integer> postorderTraversal(TreeNode root) {
if(root == null) return lists;
postorderTraversal(root.left);
postorderTraversal(root.right);
lists.add(root.val);
return lists;
}
}
class Solution {
public List<Integer> postorderTraversal(TreeNode root) {
LinkedList<TreeNode> stack = new LinkedList<>();
LinkedList<Integer> output = new LinkedList<>();
if (root == null) {
return output;
}
stack.add(root);
while (!stack.isEmpty()) {
TreeNode node = stack.pollLast();
output.addFirst(node.val);
if (node.left != null) {
stack.add(node.left);
}
if (node.right != null) {
stack.add(node.right);
}
}
return output;
}
}
非递归
class Solution {
public List<Integer> postorderTraversal(TreeNode root) {
List<Integer> ans = new LinkedList<>();
if (root == null) return ans;
Stack <TreeNode> stack = new Stack<>();
stack.push(root);
TreeNode node;
while (!stack.isEmpty()) {
node = stack.pop();
ans.add(0, node.val);
if (node.left != null) {
stack.push(node.left);
}
if (node.right != null) {
stack.push(node.right);
}
}
return ans;
}
}








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