#include<iostream>
using namespace std;
int main() {
int m, n;
cin >> n >> m;
m %= n; //这里取余后只要移动一个周期
int *a = new int[n];
for (int i = 0; i < n; i++)
cin >> a[i];
int t = n - m;
for (int i = 0; i < n; i++) {
cout << a[t++%n];
if (i != n - 1)
cout << " ";
}
return 0;
}
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