LeetCode-832-翻转图像

Python3代码：

class Solution:
    def flipAndInvertImage(self, A: List[List[int]]) -> List[List[int]]:
        for i in range(len(A)):
            l = len(A[i])
            for j in range(l//2): 
                A[i][j], A[i][l-1-j] = A[i][l-1-j], A[i][j]
            for j in range(l):
                A[i][j] = 1 - A[i][j]
        return A

class Solution:
    def flipAndInvertImage(self, A: List[List[int]]) -> List[List[int]]:
        for i in range(len(A)):
            l = len(A[i])
            for j in range((l+1)//2): 
                A[i][j], A[i][l-1-j] = 1-A[i][l-1-j], 1-A[i][j]
        return A