Java 中正则表达式如何匹配竖线(|)

在Java中直接调用String的split方法:

    val b = java.lang.String(a)
    val s3 = b.split("|") // ["a","b","c","|","1","2","3","4"]
    println(JSON.toJSONString(s3))

因为 | 在正则表达式中是或的概念，要想匹配就得用转移字符 "|" 但是 "" 又是java的转移字符，要让其在正则中起作用，就得使用: "\|"

    val b = java.lang.String(a)
    val s3 = b.split("|")
    println(JSON.toJSONString(s3)) // ["a","b","c","|","1","2","3","4"]
    val s4 = b.split("\\|")
    println(JSON.toJSONString(s4)) // ["abc","1234"]

这个Java 中的 split 方法设计简直就是一个"天坑"(天然的坑): 如果不看实现代码,很容易犯错.

public String[] split(String regex) {
        return split(regex, 0);
    }

public String[] split(String regex, int limit) {
        /* fastpath if the regex is a
         (1)one-char String and this character is not one of the
            RegEx's meta characters ".$|()[{^?*+\\", or
         (2)two-char String and the first char is the backslash and
            the second is not the ascii digit or ascii letter.
         */
        char ch = 0;
        if (((regex.value.length == 1 &&
             ".$|()[{^?*+\\".indexOf(ch = regex.charAt(0)) == -1) ||
             (regex.length() == 2 &&
              regex.charAt(0) == '\\' &&
              (((ch = regex.charAt(1))-'0')|('9'-ch)) < 0 &&
              ((ch-'a')|('z'-ch)) < 0 &&
              ((ch-'A')|('Z'-ch)) < 0)) &&
            (ch < Character.MIN_HIGH_SURROGATE ||
             ch > Character.MAX_LOW_SURROGATE))
        {
            int off = 0;
            int next = 0;
            boolean limited = limit > 0;
            ArrayList<String> list = new ArrayList<>();
            while ((next = indexOf(ch, off)) != -1) {
                if (!limited || list.size() < limit - 1) {
                    list.add(substring(off, next));
                    off = next + 1;
                } else {    // last one
                    //assert (list.size() == limit - 1);
                    list.add(substring(off, value.length));
                    off = value.length;
                    break;
                }
            }
            // If no match was found, return this
            if (off == 0)
                return new String[]{this};

            // Add remaining segment
            if (!limited || list.size() < limit)
                list.add(substring(off, value.length));

            // Construct result
            int resultSize = list.size();
            if (limit == 0) {
                while (resultSize > 0 && list.get(resultSize - 1).length() == 0) {
                    resultSize--;
                }
            }
            String[] result = new String[resultSize];
            return list.subList(0, resultSize).toArray(result);
        }
        return Pattern.compile(regex).split(this, limit);
    }

在Kotlin 中, 直接优化了这个 split 方法:

    val a = "abc|1234"

    val s1 = a.split("|")
    val s2 = a.split("\\|")

    println(s1) // [abc, 1234]
    println(s2) // [abc|1234]

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