461. Hamming Distance

作者: XYZ7 | 来源:发表于2017-02-24 15:10 被阅读0次

Leetcode 461. Hamming Distance
461. Hamming Distance
461. Hamming Distance
461. Hamming Distance
461. Hamming Distance
461. Hamming Distance
461. Hamming Distance
461. Hamming Distance
461. Hamming Distance
461. Hamming Distance

思路
从两个数的二进制最低位开始比较，每比较一位就除2并继续比较最低位，直到两个数全为0时停止。
代码

class Solution {
public:
    int hammingDistance(int x, int y) {
        int count = 0;
        while(x != 0 || y != 0) {
            if(x % 2 != y % 2)
                count++;
            x /= 2;
            y /= 2;
        }
        return count;
    }
};

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461. Hamming Distance
思路从两个数的二进制最低位开始比较，每比较一位就除2并继续比较最低位，直到两个数全为0时停止。代码
461. Hamming Distance
题目的要求是得出两个整数的二进制表示下对应位数上的不同数字的位数。下方是官网给出的范例，可以帮助理解。这个题目要...
461. Hamming Distance
Java Java，很简练，用到了库函数

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