java内存参数对齐问题

最近在做JVM调优时发现个问题，感觉比较有趣，特记录下：
JVM参数配置：

-Xms2048m -Xmx2048m -XX:PermSize=256m -XX:MaxPermSize=512m -XX:+UseConcMarkSweepGC -XX:+PrintGCDetails -XX:+PrintTenuringDistribution 

GC日志为

12083.607: [GC12083.607: [ParNew Desired survivor size 35782656 bytes, new threshold 6 (max 6)
- age   1:     186216 bytes,     186216 total
- age   2:       2328 bytes,     188544 total
- age   3:      21888 bytes,     210432 total
- age   4:      63880 bytes,     274312 total
- age   5:      63280 bytes,     337592 total
- age   6:   10588168 bytes,   10925760 total
: 574751K->15677K(629120K), 0.0072360 secs] 603265K->44191K(2027264K), 0.0074590 secs] [Times: user=0.12 sys=0.00, real=0.00 secs] 

我们都知道默认情况下

1. NewRatio=2,NewRatio=Old/Yong=Old/(Eden+Survivor*2)
2. SurvivorRatio=8,SurvivorRatio=Eden/Survivor
3. TargetSurvivorRatio=0.5

根据上面的配置，Survivor的大小为 204810241024/3/10bytes=71582789，而日志中的 Desired survivor size（DSS)=SurvivorTargetSurvivorRatio=35782656,可以推算出Survivor=357826562=71565312,可以看到两个结果存在差异，那么原因在哪呢？
查看JVM的源码发现Survivor大小是这么计算的:

size_t compute_survivor_size(size_t gen_size, size_t alignment) const {
    size_t n = gen_size / (SurvivorRatio + 2);
    return n > alignment ? align_size_down(n, alignment) : alignment;
  }

#define align_size_down_(size, alignment) ((size) & ~((alignment) - 1))

enum SomePublicConstants {
    // Generations are GenGrain-aligned and have size that are multiples of
    // GenGrain.
    // Note: on ARM we add 1 bit for card_table_base to be properly aligned
    // (we expect its low byte to be zero - see implementation of post_barrier)
    LogOfGenGrain = 16 ARM_ONLY(+1),
    GenGrain = 1 << LogOfGenGrain
  };

原来计算survivor大小时，需要进行对齐操作；

71582789&~((1<<16)-1)=71565312